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RUMC_2020
HSC - উচ্চতর গণিত ১ম পত্র
→
অধ্যায়-১০ঃ যোগজীকরণ
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All Topics
f
(
θ
)
=
sin
θ
f(\theta)=\sin \theta
f
(
θ
)
=
sin
θ
এবং
g
(
x
)
=
e
m
sin
−
1
2
x
g(x)=e^{m \sin ^{-1} 2 x}
g
(
x
)
=
e
m
s
i
n
−
1
2
x
ক. যদি
△
A
B
C
\triangle \mathrm{ABC}
△
ABC
এ
B
C
=
a
,
C
A
=
b
,
A
B
=
c
\mathrm{BC}=\mathrm{a}, \mathrm{CA}=\mathrm{b}, \mathrm{AB}=\mathrm{c}
BC
=
a
,
CA
=
b
,
AB
=
c
এবং
a
4
+
b
4
+
c
4
=
2
c
2
(
a
2
+
b
2
)
a^{4}+b^{4}+c^{4}=2 c^{2}\left(a^{2}+b^{2}\right)
a
4
+
b
4
+
c
4
=
2
c
2
(
a
2
+
b
2
)
হয়, তবে দেখাও যে,
C
=
4
5
∘
C=45^{\circ}
C
=
4
5
∘
অথবা,
13
5
∘
135^{\circ}
13
5
∘
খ. প্রমাণ কর যে,
(
1
−
4
x
2
)
g
′
′
(
x
)
−
4
x
⋅
g
′
(
x
)
=
4
m
2
g
(
x
)
\left(1-4 x^{2}\right) g^{\prime \prime}(x)-4 x \cdot g^{\prime}(x)=4 m^{2} g(x)
(
1
−
4
x
2
)
g
′′
(
x
)
−
4
x
⋅
g
′
(
x
)
=
4
m
2
g
(
x
)
গ. i. যোগজ নির্ণয় কর :
∫
d
θ
1
+
3
{
f
(
π
2
−
θ
)
}
2
\int \frac{d \theta}{1+3\left\{f\left(\frac{\pi}{2}-\theta\right)\right\}^{2}}
∫
1
+
3
{
f
(
2
π
−
θ
)
}
2
d
θ
ii. মান নির্ণয় কর :
∫
0
π
2
{
f
(
π
2
−
x
)
}
3
f
(
x
)
d
x
\int_{0}^{\frac{\pi}{2}}\left\{f\left(\frac{\pi}{2}-x\right)\right\}^{3} \sqrt{f(x)} d x
∫
0
2
π
{
f
(
2
π
−
x
)
}
3
f
(
x
)
d
x
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