$\int \frac{\left(\tan x+\tan ^{3} x\right) d x}{e^{\sec ^{2} x}+e^{-sec^{2} x}}$ এর মান হলো-

$\frac{1}{2} \tan ^{-1}\left(e^{sec^{2} x}\right)+c$

$\tan ^{-1}\left(\frac{1}{2} e^{sec^{2} x}\right)+c$

$2 \tan ^{-1}\left(e^{\sec ^{2} x}\right)$

$\tan ^{-1}\left(2 e^{sec{2} x}\right)+c$

$\frac{1}{2} \tan ^{-1}\left(e^{sec{2} x}\right)+c$