$\mathrm {\Large{\int} \normalsize \dfrac{1}{x^{2}} d x}=$ কত? $\mathrm {x \ne 0}$

$\mathrm {-\dfrac{1}{3 x^{3}}+c}$

$\mathrm {-\dfrac{1}{ x}+c}$

$\mathrm {\dfrac{1}{3 x^{3}}+c}$

$\mathrm {\dfrac{1}{ x}+c}$