$\sin \theta+1=0$ হলে $\theta=?$

$(4 n-1) \frac{\pi}{2}, n \in z$

$(4 n+1) \frac{\pi}{2}, n \in z$

$(2 n+1) \frac{\pi}{2}, n \in z$

$(2 \mathrm{n}-1) \pi, \mathrm{n} \in \mathrm{z}$