(2n+1)π12,n∈Z(2 n+1) \frac{\pi}{12}, n \in \mathbb{Z}(2n+1)12π,n∈Z
(2n+1)π6,n∈Z(2 n+1) \frac{\pi}{6}, n \in \mathbb{Z}(2n+1)6π,n∈Z
(2n+1)π3,n∈Z(2 \mathrm{n}+1) \frac{\pi}{3}, \mathrm{n} \in \mathbb{Z}(2n+1)3π,n∈Z
(2n+1)π,n∈Z(2 \mathrm{n}+1) \pi, \mathrm{n} \in \mathbb{Z}(2n+1)π,n∈Z