∇ˉ×Bˉ=0\bar{\nabla} \times \bar{B}=0∇ˉ×Bˉ=0
∇ˉ×Bˉ≠0\bar{\nabla} \times \bar{B} \neq 0∇ˉ×Bˉ=0
∇ˉ⋅Bˉ=0\bar{\nabla} \cdot \bar{B}=0∇ˉ⋅Bˉ=0
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