$2 \sin 2 \theta=1$ সমীকরণটির সাধারণ সমাধান—

$n \pi-(-1)^{n} \frac{\pi}{6}, n \in \mathbb{Z}$

$\mathrm{n} \pi+(-1)^{\mathrm{n}} \frac{\pi}{6}, \mathrm{n} \in \mathbb{Z}$

$\frac{n \pi}{2}-(-1)^{n} \frac{\pi}{12}, n \in \mathbb{Z}$

$\frac{\mathrm{n} \pi}{2}+(-1)^{\mathrm{n}} \frac{\pi}{12}, \mathrm{n} \in \mathbb{Z}$