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SB_2021
HSC - উচ্চতর গণিত ১ম পত্র
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অধ্যায়-১০ঃ যোগজীকরণ
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f
(
θ
)
=
cos
2
θ
f(\theta)=\cos 2 \theta
f
(
θ
)
=
cos
2
θ
হলে -
i.
∫
f
(
θ
)
d
θ
\text{i. } \int f(\theta) \mathrm{d} \theta
i.
∫
f
(
θ
)
d
θ
=
sin
2
θ
2
+
c
=\frac{\sin 2 \theta}{2}+\mathrm{c}
=
2
s
i
n
2
θ
+
c
ii.
∫
1
−
f
(
θ
)
d
θ
\text{ii. } \int \sqrt{1-f(\theta)} d \theta
ii.
∫
1
−
f
(
θ
)
d
θ
=
−
2
cos
θ
+
c
=-\sqrt{2} \cos \theta+c
=
−
2
cos
θ
+
c
iii.
∫
1
+
f
(
θ
)
d
θ
\text{iii. } \int \sqrt{1+f(\theta)} d \theta
iii.
∫
1
+
f
(
θ
)
d
θ
=
2
sin
θ
+
c
=\sqrt{2} \sin \theta+c
=
2
sin
θ
+
c
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