−i^−2k^-\hat{\mathrm{i}}-2 \hat{\mathrm{k}}−i^−2k^
−3i^−6k^-3 \hat{i}-6 \hat{k}−3i^−6k^
−3(i^+2k^)45\frac{-3(\hat{i}+2 \hat{k})}{\sqrt{45}}45−3(i^+2k^)
−3(i^−2k^)45\frac{-3(\hat{\mathrm{i}}-2 \hat{\mathrm{k}})}{\sqrt{45}}45−3(i^−2k^)
