RUET_06-07

(a)(a) সমাধান কর: (secx+tanx)2(sec2x+tanx)2sin2xsinx=2;[πxπ]\frac{(\sec x+\tan x)^{2}-(\sec 2 x+\tan x)^{2}}{\sin 2 x-\sin x}=2 ; \quad[-\pi \leq x \leq \pi](b)(b) ABC\triangle A B C থেকে প্রমাণ কর যে, a2(sin2Bsin2C)+b2(sin2Csin2A)+c2(sin2Asin2B)=0a^{2}\left(\sin ^{2} B-\sin ^{2} C\right)+b^{2}\left(\sin ^{2} C-\sin ^{2} A\right)+c^{2}\left(\sin ^{2} A-\sin ^{2} B\right)=0

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