$\int_{0}^{1} \frac{\tan ^{-1} x}{1+x^{2}} d x=?$

$\frac{\pi^{2}}{16}$

$\frac{\pi}{8}$

$\frac{\pi}{4}$

$\frac{\pi}{2}$

$\frac{\pi}{8}$

$\text { No correct answer }$