$\sin ^{2} 2 \theta-3 \cos ^{2} \theta=0,(\cos \theta \neq 0)$ সমীকরণের সাধারণ সমাধান—

$\mathrm{n} \pi+\frac{\pi}{6}$

$\mathrm{n} \pi-\frac{\pi}{6}$

$\mathrm{n} \pi \pm \frac{\pi}{3}$

$2 n \pi \pm \frac{\pi}{6}$