ln(1+lnx)+C\ln (1+\ln x)+Cln(1+lnx)+C
−11+lnx+C-\frac{1}{1+\ln x}+C−1+lnx1+C
−1ln∣x∣+C-\frac{1}{\ln |x|}+C−ln∣x∣1+C
x+lnx+Cx+\ln x+Cx+lnx+C