RUMC_2020

p=sin2α,q=sin2β,r=cos2α,s=cos2β,t=sin2γp=\sin 2 \alpha, q=\sin 2 \beta, r=\cos 2 \alpha, s=\cos 2 \beta, t=\sin 2 \gammaক. প্রমাণ কর যে, sec3x2=224+8+8cos6x\sec \frac{3 x}{2}=\frac{2 \sqrt{2}}{\sqrt{4+\sqrt{8+8 \cos 6 x}}}খ. p+q=c,r+s=d\mathbf{p}+\mathbf{q}=\mathbf{c}, \mathrm{r}+\mathrm{s}=\mathrm{d} হলে, দেখাও যে,cos(2α+2β)=d2c2d2+c2\cos (2 \alpha+2 \beta)=\frac{d^{2}-c^{2}}{d^{2}+c^{2}}গ. α+β+γ=π\alpha+\beta+\gamma=\pi হলে, দেখাও যে, p2+q2+t2=22 rs. cos2γp^{2}+q^{2}+t^{2}=2-2 \text { rs. } \cos 2 \gamma

Loading answers...