(4n−1)π4;n∈Z(4 n-1) \frac{\pi}{4} ; n \in \mathbb{Z}(4n−1)4π;n∈Z
(4n+1))π4;n∈Z(4 n+1)) \frac{\pi}{4} ; n \in \mathbb{Z}(4n+1))4π;n∈Z
(8n−1)π4;n∈Z(8 n-1) \frac{\pi}{4} ; n \in \mathbb{Z}(8n−1)4π;n∈Z
(8n+1)π4;n∈Z(8 n+1) \frac{\pi}{4} ; n \in \mathbb{Z}(8n+1)4π;n∈Z
