A\B=A∪B′\mathrm{A} \backslash \mathrm{B}=\mathrm{A} \cup \mathrm{B}^{\prime}A\B=A∪B′
A\B=A∩B′A \backslash B=A \cap B^{\prime}A\B=A∩B′
A\B=A′∪B\mathrm{A} \backslash \mathrm{B}=\mathrm{A}^{\prime} \cup \mathrm{B}A\B=A′∪B
A\B=A′∪BA \backslash B=A^{\prime} \cup BA\B=A′∪B