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CUET_15-16
HSC - রসায়ন ২য় পত্র
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অধ্যায়-০৪ঃ তড়িৎ রসায়ন
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নিচের কোষটির EMF কত?
Z
n
∣
Z
n
2
+
(
0.001
M
i
)
∥
A
g
+
(
0.1
M
)
∣
A
g
[
E
c
e
l
l
0
=
1.56
V
\mathrm{Zn}\left|\mathrm{Zn}^{2+}(0.001 \mathrm{Mi}) \| \mathrm{Ag}^{+}(0.1 \mathrm{M})\right| \mathrm{Ag}\left[\mathrm{E}_{\mathrm{cell}}^{0}=1.56 \mathrm{~V}\right.
Zn
Zn
2
+
(
0.001
Mi
)
∥
Ag
+
(
0.1
M
)
Ag
[
E
cell
0
=
1.56
V
A.
1.59 V
B.
1.46 V
C.
1.61 V
D.
1.10 V
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