θ=2nπ+π2\theta=2 \mathrm{n} \pi+\frac{\pi}{2}θ=2nπ+2π
θ=(2n+1)π2\theta=(2 n+1) \frac{\pi}{2}θ=(2n+1)2π
θ=(2n−1)π2\theta=(2 n-1) \frac{\pi}{2}θ=(2n−1)2π
θ=2nπ−π2\theta=2 \mathrm{n} \pi-\frac{\pi}{2}θ=2nπ−2π