k=3,α=13\mathrm{k}=3, \alpha=\frac{1}{3}k=3,α=31
k=1,α=13\mathrm{k}=1, \alpha=\frac{1}{3}k=1,α=31
k=3,α=−1\mathrm{k}=3, \alpha=-1k=3,α=−1
k=0,α=1\mathrm{k}=0, \alpha=1k=0,α=1