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CB_2023
HSC - উচ্চতর গণিত ১ম পত্র
→
অধ্যায়-০৯ঃ অন্তরীকরণ
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All Topics
x
→
0
lim
tan
−
1
x
2
3
x
=
\large{\mathrm {\overset{\lim}{ _{x \rightarrow 0}}~ \frac{\tan ^{-1} \frac{x}{2}}{3 x}=}}
x
→
0
l
i
m
3x
t
a
n
−
1
2
x
=
কত ?
A.
1
6
\frac{1}{6}
6
1
B.
1
3
\frac{1}{3}
3
1
C.
1
2
\frac{1}{2}
2
1
D.
3
2
\frac{3}{2}
2
3
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