Search
Bookmarks
My requests
Create/Join exam
Test Series
Mock tests
?
Sign In
Click to login or register
Toggle Sidebar
SB_2023
HSC - উচ্চতর গণিত ১ম পত্র
→
অধ্যায়-০৯ঃ অন্তরীকরণ
→
All Topics
x
→
0
lim
(
1
+
3
x
)
4
x
=
?
{\mathrm { \overset{\lim}{ _{x \rightarrow \ 0}}\left(1+\frac{3}{x}\right)^{4 x}=?}}
x
→
0
l
i
m
(
1
+
x
3
)
4x
=
?
A.
e
4
3
\mathrm e^{\frac{4}{3}}
e
3
4
B.
e
12
\mathrm e^{12}
e
12
C.
3
e
12
\mathrm 3e^{12}
3
e
12
D.
1
Guide Answer
Add Answer
?
Loading answers...
