2nπ2 \mathrm{n} \pi2nπ
(2n+1)π(2 n+1) \pi(2n+1)π
2nπ+π42 \mathrm{n} \pi+\frac{\pi}{4}2nπ+4π
(2n−1)π(2 n-1) \pi(2n−1)π