HSC - রসায়ন ২য় পত্র→অধ্যায়-০৪ঃ তড়িৎ রসায়ন→All Topics

If a current of $\text {5A}$ is passed through a $\mathrm {CuSO_4}$ solution for $15$ minutes, the amount of copper will be deposited on the cathode will be- $\text {[Cu = 63.5]}$