i^×i^=j^\hat{i} \times \hat{i}=\hat{j}i^×i^=j^
i^×i^=1\hat{i} \times \hat{i}=1i^×i^=1
i^×i^=0\hat{i} \times \hat{i}=0i^×i^=0
i^×i^=k^\hat{i} \times \hat{i}=\hat{k}i^×i^=k^