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BUET_23-24
HSC - রসায়ন ২য় পত্র
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অধ্যায়-০৪ঃ তড়িৎ রসায়ন
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N
i
/
N
i
2
+
∥
A
g
+
A
g
\mathbf{N i} / \mathrm{Ni}^{2^{+}} \| \mathbf{A g}^{+} \mathbf{A g}
Ni
/
Ni
2
+
∥
Ag
+
Ag
কোষের জন্য-
N
i
2
+
+
2
e
‾
⟶
N
i
\mathrm{Ni}^{2+}+2 \overline{\mathrm{e}} \longrightarrow \mathrm{Ni}
Ni
2
+
+
2
e
⟶
Ni
~~~~~~
E
0
=
−
0.25
V
E^{0}=-0.25 V
E
0
=
−
0.25
V
A
g
+
+
e
‾
⟶
A
g
\mathbf{A g}^{+}+\overline{\mathbf{e}} \longrightarrow \mathbf{A g}
Ag
+
+
e
⟶
Ag
~~~~~~
E
0
=
+
0.80
V
\mathrm{E}^{0}=+0.80 \mathrm{~V}
E
0
=
+
0.80
V
E
cell
0
\mathbf{E}_{\text {cell }}^{0}
E
cell
0
কত হবে?
A.
1.05V
B.
-1.05V
C.
0.55V
D.
-0.55V
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