$\sin \theta=\frac{\sqrt{3}}{2}$ হলে $\theta=$ কত?

$\mathrm{n} \pi+(-1)^{n} \frac{\pi}{6}, n \in \mathbb{Z}$

$2 n \pi+(-1)^{n} \frac{\pi}{6}, n \in \mathbb{Z}$

$n \pi+(-1)^{n} \frac{\pi}{3}, n \in \mathbb{Z}$

$2 n \pi+(-1)^{n} \frac{\pi}{3} ; n \in \mathbb{Z}$