asinθ=(2n+1)λ2a \sin \theta=(2 n+1) \dfrac{\lambda}{2} asinθ=(2n+1)2λ
asinθ=nλa\sin \theta =n\lambda asinθ=nλ
asinθ=nλ2a\sin \theta =n\dfrac{\lambda }{2}asinθ=n2λ
asinθ=(2n+1)λa\sin \theta =(2n+1)\lambda asinθ=(2n+1)λ