$\cot ^{2} \theta-(\sqrt{3}+1) \cot \theta+\sqrt{3}=0,0<\theta<\frac{\pi}{2}, \theta=$ কত ?

$\frac{\pi}{6}, \frac{\pi}{3}$

$\frac{\pi}{4}, \frac{\pi}{3}$

$\frac{\pi}{3}, \frac{\pi}{5}$

$\frac{\pi}{6}, \frac{\pi}{4}$