14[3sin(nπ/2+x)−3nsin(nπ/2+3x)]\frac{1}{4}\left[3 \sin (n \pi / 2+x)-3^{n} \sin (n \pi / 2+3 x)\right]41[3sin(nπ/2+x)−3nsin(nπ/2+3x)]
sin(nπ/2+x)\sin (n \pi / 2+x)sin(nπ/2+x)
cos(π/2+x)\cos (\pi / 2+x)cos(π/2+x)
3nsin(nπ/2+3x)3^{n} \sin (n \pi / 2+3 x)3nsin(nπ/2+3x)
3nsin(nπ/2+3x)+cosnx3^{n} \sin (n \pi / 2+3 x)+\cos n x3nsin(nπ/2+3x)+cosnx