DU-A_16-17

 If tan1(x+13)+tan1(x13)=tan12, then the value of x is \text { If } \tan ^{-1}\left(x+\frac{1}{3}\right)+\tan ^{-1}\left(x-\frac{1}{3}\right)=\tan ^{-1} 2 \text {, then the value of } x \text { is }-

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