ln(1−5x)+c\ln (1-5 x)+cln(1−5x)+c
−ln(1−5x)+c-\ln (1-5 x)+c−ln(1−5x)+c
ln(1−5x)5\frac{\ln (1-5 x)}{5}5ln(1−5x)
−ln(1−5x)5\frac{-\ln (1-5 x)}{5}5−ln(1−5x)