Search
Bookmarks
My requests
Create/Join exam
Test Series
Mock tests
?
Sign In
Click to login or register
Toggle Sidebar
IUT_10-11
HSC - রসায়ন ২য় পত্র
→
অধ্যায়-০৪ঃ তড়িৎ রসায়ন
→
All Topics
What is the emf of the following half-cell at
4
7
∘
C
?
[
E
o for
F
e
=
0.036
V
]
:
F
e
l
F
e
C
l
3
(
0.25
M
)
47^{\circ} \mathrm{C} ?\left[\mathrm{E}^{\text {o for }} \mathrm{Fe}=0.036 \mathrm{~V}\right]: \mathrm{FelFeCl}_{3}(0.25 \mathrm{M})
4
7
∘
C
?
[
E
o for
Fe
=
0.036
V
]
:
FelFeCl
3
(
0.25
M
)
A.
0.0478 V
B.
0.0487 V
C.
0.0742 V
D.
0.4781 V
Guide Answer
Add Answer
?
Loading answers...
Home
Search
Exam
Mock
Saved
