nλ\text{n}\lambda nλ
(n+1)λ2\dfrac{(\text{n}+1)\lambda }{2}2(n+1)λ
(2n+1)λ2\dfrac{(2\text{n}+1)\lambda }{2}2(2n+1)λ
(2n−1)λ2\dfrac{(2\text{n}-1)\lambda }{2}2(2n−1)λ