$\int \sin \left(10-\frac{x}{5}\right) d x=$ কত ?

$5 \cos \left(10-\frac{x}{5}\right)+c$

$-5 \cos \left(10-\frac{x}{5}\right)+c$

$-\frac{1}{5} \cos \left(10-\frac{x}{5}\right)+c$

$\frac{1}{5}\left(10-\frac{x}{5}\right)+c$