xln∣x∣+xx \ln |x|+xxln∣x∣+x
xln∣1x∣+xx \ln \left|\frac{1}{x}\right|+xxlnx1+x
1xlnx∣1x∣+x\frac{1}{x} \ln x\left|\frac{1}{x}\right|+xx1lnxx1+x
1xln∣1x∣+1x\frac{1}{x} \ln \left|\frac{1}{x}\right|+\frac{1}{x}x1lnx1+x1