$2\left(\cos ^{2} \theta-\sin ^{2} \theta\right)=\sqrt{3} এর সাধারণ সমাধান -

$2 n \pi \pm \frac{\pi}{6}$

$n \pi \pm \frac{\pi}{6}$

$2 n \pi \pm \frac{\pi}{12}$

$\mathrm{n} \pi \pm \frac{\pi}{12}$