$\sin \theta=\frac{\sqrt{3}}{2}$ হলে $\boldsymbol{\theta}=$ কত ?

$n \pi+(-1)^{n} \frac{\pi}{6}, n \in \mathbb{Z}$

$2 n \pi+(-1)^{n} \frac{\pi}{6}, n \in \mathbb{Z}$

$\pi+(-1)^{n} \frac{\pi}{3}, n \in \mathbb{Z}$

$2 n \pi+(-1)^{n} \frac{\pi}{3}, n \in \mathbb{Z}$