$-\pi \leq \mathrm{x} \leq \pi$ ব্যবধিতে $\sin x=-\frac{1}{2}$ সমীকরণের সা সমাধান-

$-\frac{\pi}{6},-\frac{5 \pi}{6}$

$-\frac{\pi}{6}, \frac{5 \pi}{6}$

$\frac{\pi}{6},-\frac{5 \pi}{6}$

$\frac{\pi}{6}, \frac{5 \pi}{6}$