2nπ±α2 \mathrm{n} \pi \pm \alpha2nπ±α
nπ±αn \pi \pm \alphanπ±α
2nπ+(−)nα2 n \pi+(-)^{n} \alpha2nπ+(−)nα
(2n+1)π2±α(2 n+1) \frac{\pi}{2} \pm \alpha(2n+1)2π±α