$\text { Suppose } f(x)=\sqrt{x}+1 \text {, then } f(x+h)=\text { ? }$

$\sqrt{x}+h+1$

$\sqrt{\mathrm{x}+\mathrm{h}}+1$

$\sqrt{x+h+1}$

$\sqrt{\mathrm{x}}+\sqrt{\mathrm{h}+1}$