12∣Aˉ×Bˉ∣\frac{1}{2}|\bar{A} \times \bar{B}|21∣Aˉ×Bˉ∣
Λˉ×Bˉ\bar{\Lambda} \times \bar{B}Λˉ×Bˉ
12(Aˉ×Bˉ)\frac{1}{2}(\bar{A} \times \bar{B})21(Aˉ×Bˉ)
∣Aˉ×Bˉ∣|\bar{A} \times \bar{B}|∣Aˉ×Bˉ∣