12(e2x+1)+c\frac{1}{2\left(e^{2 x}+1\right)}+c2(e2x+1)1+c
−12(e2x+1)+c\frac{-1}{2\left(e^{2 x}+1\right)}+c2(e2x+1)−1+c
12e2x+c\frac{1}{2 e^{2 x}}+c2e2x1+c
−12e2x+c\frac{-1}{2 e^{2 x}}+c2e2x−1+c