(2n+1)π/4(2 n+1) \pi / 4(2n+1)π/4
(2n+1)π/8(2 n+1) \pi / 8(2n+1)π/8
nπ/4\mathrm{n} \pi / 4nπ/4
(2n−1)π/2(2 n-1) \pi / 2(2n−1)π/2