লুকাস বিকারক হলো-

$\text { conc. } \mathrm{HCl}+\text { Anhydrous } \mathrm{ZnCl}_{2}$

$\text { dil } \cdot \mathrm{HCl}+\mathrm{ZnCl}_{2}$

$\text {conc. } \mathrm{HNO}_{3}+\mathrm{ZnCl}_{2}$

$\text { conc. } \mathrm{H}_{2} \mathrm{SO}_{4}+\text { Anhydrous } \mathrm{ZnCl}_{2}$

$\text { None of the above }$