0.25πAm20.25 \pi \mathrm{Am}^{2}0.25πAm2
0.25Am20.25 \mathrm{Am}^{2}0.25Am2
I=B−μ0Hμ0I=\frac{B-\mu_{0} H}{\mu_{0}}I=μ0B−μ0H
X=μ−1X=\mu-1X=μ−1
