DB_2022

tanθ=3\tan \theta=\sqrt{3} হলে-i.sin2θ=32ii.cos2θ=12iii.tan2θ=3\begin{array}{l}\text{i.} \quad \sin 2 \theta =\frac{\sqrt{3}}{2}\\\text{ii.} \cos 2 \theta=\frac{1}{2}\\\text{iii.} \tan 2 \theta=-\sqrt{3}\end{array}নিচের কোনটি সঠিক?

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