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PUST-A_12-13
HSC - উচ্চতর গণিত ১ম পত্র
→
অধ্যায়-০২ঃ ভেক্টর (HSC - গণিত)
→
সমন্বিত টপিক
A
⃗
\vec{A}
A
=
3
i
⃗
+
j
⃗
−
2
k
⃗
,
=3 \vec{i}+\vec{j}-2 \vec{k},
=
3
i
+
j
−
2
k
,
B
⃗
=
2
i
⃗
−
j
⃗
+
k
⃗
,
C
⃗
\vec{B}=2 \vec{i}-\vec{j}+\vec{k}, \vec{C}
B
=
2
i
−
j
+
k
,
C
=
i
⃗
+
3
j
⃗
−
2
k
⃗
=\vec{i}+3 \vec{j}-2 \vec{k}
=
i
+
3
j
−
2
k
হলে
B
→
⋅
(
C
→
+
A
→
)
\overrightarrow{\mathrm{B}} \cdot(\overrightarrow{\mathrm{C}}+\overrightarrow{\mathrm{A}})
B
⋅
(
C
+
A
)
=
?
=\text { ? }
=
?
A.
1
1
1
B.
0
0
0
C.
2
2
2
D.
3
3
3
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