$\sin A=\frac{1}{\sqrt{2}}, \sin B=\frac{1}{\sqrt{3}}$ হলে $\tan (A+B)=$ কত ?

$\frac{1-\sqrt{2}}{1+\sqrt{2}}$

$\frac{1+\sqrt{2}}{1-\sqrt{2}}$

$\frac{\sqrt{2}-1}{\sqrt{2}+1}$

$\frac{\sqrt{2}+1}{\sqrt{2}-1}$