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IUT_17-18
HSC - উচ্চতর গণিত ২য় পত্র
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অধ্যায়-০৩ঃ জটিল সংখ্যা
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If
i
2
=
−
1
, then
(
8
+
6
i
)
=
?
i^2=-1\text{, then }\sqrt{(8+6i)}=\text{ ? }
i
2
=
−
1
, then
(
8
+
6
i
)
=
?
A.
(
3
+
i
)
(3+i)
(
3
+
i
)
B.
−
(
3
+
i
)
-(3+i)
−
(
3
+
i
)
C.
±
(
3
+
i
)
\pm(3+i)
±
(
3
+
i
)
D.
(
3
−
i
)
(3-i)
(
3
−
i
)
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