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DiB_2022
HSC - উচ্চতর গণিত ১ম পত্র
→
অধ্যায়-০৯ঃ অন্তরীকরণ
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All Topics
f
(
x
)
=
tan
−
1
(
2
x
1
−
x
2
)
f(x)=\tan ^{-1}\left(\frac{2 x}{1-x^{2}}\right)
f
(
x
)
=
tan
−
1
(
1
−
x
2
2
x
)
এবং
g
(
x
)
=
sin
−
1
(
sin
x
)
g(x)=\sin ^{-1}(\sin \sqrt{x})
g
(
x
)
=
sin
−
1
(
sin
x
)
হলে-
i.
f
′
(
x
)
=
2
1
+
x
2
\text { i. } \quad f^{\prime}(x)=\frac{2}{1+x^{2}}
i.
f
′
(
x
)
=
1
+
x
2
2
ii.
g
′
(
x
)
=
1
x
\text { ii. } g^{\prime}(x)=\frac{1}{\sqrt{x}}
ii.
g
′
(
x
)
=
x
1
iii.
f
(
1
)
=
π
2
\text { iii. } f(1)=\frac{\pi}{2}
iii.
f
(
1
)
=
2
π
নিচের কোনটি সঠিক?
A.
i ও ii
B.
ii ও iii
C.
i ও iii
D.
i, ii ও iii
Guide Answer
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f(x)=\tan ^{-1}\left(\frac{2 x}{1-x^{2}}\right) এবং g(x)=\sin ^{-1}(\sin \sqrt{x}) হলে- \text { i. } \quad f^{\prime}(x)=\frac{2}{1+x^{2}} \text { ii. } g^{\prime}(x)=\frac{1}{\sqrt{x}} \text { iii. } f(1)=\frac{\pi}{2} নিচের কোনটি সঠিক?
